1.where is the number 3 − 7 located on a horizontal number line?

a: 4 units to the left of 3
b: 7 units to the left of 3
c: 4 units to the right of 3
d: 7 units to the right of 3

2.simplify 7 + (−3).

a: −10

b: −4

c: 4

d: 10

3-7 = -4 

-4 -3 -2 -1 0 1 2 3 4 5 
 1u2u3u4u5u6u7u   so from this result that 7 units to the left of 3
 
 hope this is understandably                     

Looking at this problem, you know that 3 - 7 will be B: 7 units to the left of 3. One way to know this is because you subtracted 7 from 3, meaning you took it away. When you take away, you go left on the number line, and you took away 7, so you went 7 left.



7 + (-3)

When you add a negative number, it is the same as subtracting the number So, instead of +(-3), it will be just -3.

7 - 3 = 4

So your answer will be C: 4

The answer to your question is b’(16,14)