A gardener is going to plant 2 red rosebushes and 2 white rosebushes. If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes?

The answer to the question is

The probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

Step-by-step explanation:

To solve the question we note that the required permutation is WRRW

Therefore the total number of ways to plant the four rose bushes given that two white rose bushes are in the middle is given by

4!/(2!2!) = 6 Therefore the probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

his chances of getting a coin of higher value is 4/19

step-by-step explanation: