It takes 12 L of petrol to raise a go-kart for 20 minutes petrol costs 137 per litre six go-karts are use 18 L of petrol how many minutes did they race for ?

For 18 L petrol 6 go-kart race of 30 minutes.

Step-step explanation:

We have , 12 L of petrol to raise a go-kart for 20 minutes petrol costs 137 per litre . That means it requires 12 L of petrol to run go-kart of 20 minutes . Petrol costs 137 per L , for 12 L : 137 × 12 = 1644. Now, There are 6 go-kart which use 18 L of petrol , let's calculate,  minutes they race with 18 L:

In 12 L , 20 minutes So in 1 L , . ∴ In 18 L , amount of minutes go-kart will race is  × = . Also, cost for 18 L is : 137 ×18 = 2466.

Hence, For 18 L petrol 6 go-kart race of 30 minutes.

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.