Plz help :(
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The speed of one of the planes was 200 km/hour slower than the speed of the other plane, and so it arrived at its destination 1.5 hours after the faster plane. Find the speeds of both planes.

Step-by-step explanation:

Constant Speed Motion

Let's assume the speeds of both planes are v1 and v2 respectively, the plane 2 slower than the plane 1, thus

Solving for v1

The time the faster plane took to arrive is

The time the slower plane took to arrive is

We know that

Or, equivalently

Using x=3600 and replacing [1]

Operating

Operating and simplifying

Solving for v2:

We take the positive solution

Thus

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: