And for number 3 it’s gonna be

a) find f(0)

b) find f(2)

c) f(0) + f(2)

d) f(3) x f(-2)

e) f(0) divided by f(2)

a) f(0)=2

b)f(2)=-4

c)f(0)+f(2)=-2

d)f(3)*f(-2)=-56

e)f(0):f(2)=-1/2

Step-by-step explanation:

f(x) =-3x+2

a) f(0)=-3*0+2=2

b) f(2)=-3*2+2=-6+2=-4

c) f(0)+f(2)=2-4=-2

d)f(3)*f(-2)=-7*8=-56

f(3)=-3*3+2=-9+2=-7

f(-2)=-3*(-2)+2=6+2=8

e)f(0):f(2)=2/(-4)=-1/2

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

c: lkllmn.

hope it's you