Using factorization method, find the square roots of the quadratic equation. 3p (2p-1) - 17 = (2p-5)(square)

p = - 2, p = -

Step-by-step explanation:

Given

3p(2p - 1) - 17 = (2p - 5)² ← expand factors on both sides

6p² - 3p - 17 = 4p² - 20p + 25 ( subtract 4p² - 20p + 25 from both sides )

2p² + 17p - 42 = 0

Consider the factors of the product of the coefficient of the p² term and the constant term which sum to give the coefficient of the p- term.

product = 2 × - 42 = - 84 and sum = + 17

Factors are + 21 and - 4

Use these factors to split the p- term

2p² - 4p + 21p - 42 = 0 ( factor the first/second and third/fourth terms )

2p(p - 2) + 21(p - 2) = 0 ← factor out (p - 2) from each term

(p - 2)(2p + 21) = 0

Equate each factor to zero and solve for p

p - 2 = 0 ⇒ p = 2

2p + 21 = 0 ⇒ 2p = - 21 ⇒ p = -

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

you can use a^2+ b^2=c^2