In 1900, half of the babies born in America were born with blue eyes. Which simulation could be used to find the probability that 3 out of 4 babies born had blue eyes? A.) Toss a coin two times B.) Spin a spinner with 4 equal sections two times C.) Roll a six sided number cube two timesD.) Picks a card from 10 cards two times.

B.) Spin a spinner with 4 equal sections two times

Step-by-step explanation:

Given that half of the babies born were blue eyes, then the probability of a baby born with blue eye is 50% = 0.5

The probability that 3 out of 4 babies born had blue eyes will be;

0.5*0.5*0.5*0.5=0.0625

This case is similar to the probability of a Spin, a spinner with 4 equal sections spinned two times;

The probability of the spinner in one spin is 1/4 =0.25

If the process is done twice, the probability is : 0.25*0.25 =0.0625

This case is similar to the scenario in question.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

can you rephrase the question ? it is unclear : -)

step-by-step explanation: