Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of, f(5)? (A) 11.446 (C) 24.672 (B) 13.446 (D) 26.672 7. Let f(x) be a continuous function such that and f'lx)- (A) 11.446 (C) 24.672 6. What is the value of f(5)? (B) 13.446 (D) 26.672

f(5) = 26.672 which is option D

Step-by-step explanation:

From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.