Car A costs $10,000 and costs $0.12 per mile to maintain. Car B costs $11,000 and costs $0.11 per mile to maintain. Suppose both cars are driven the same number of miles. At what mileage would the total cost I the two cars be the same?

100,000 miles

Step-by-step explanation:

Cost of Car A = $10,000

Cost of Car B = $11,000

Let the mile at which the cost are the same =x

Car A costs $0.12 per mile to maintain i.e. $0.12x for x miles

Car B costs $0.11 per mile to maintain i.e. $0.11x for x miles

Total Cost for Car A=10000+0.12x

Total Cost for Car B=11000+0.11x

If their costs are the same at x miles

10000+0.12x=11000+0.11x

0.12x-0.11x=11000-10000

0.01x=1000

x=1000/0.01=100,000

After 100,000 miles their total cost will be the same

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09