. For vectors B⃗ =−iˆ−4jˆB→=−i^−4j^ and A⃗ =−3iˆ−2jˆA→=−3i^−2j^ , calculate (a) A⃗ +B⃗ A→+B→ and its magnitude and direction angle, and (b) A⃗ −B⃗ A→−B→ and its magnitude and direction angle.

Step-by-step explanation:

given are two vectors

a) A+B = sum of twovectors = simply adding corrsponding compnents

=

Magnitude of the above vector =

Direction is making an angle of arc tan (-3) with x axis

b) A-B = Difference

=

Magnitude of difference vector =

Direction is making an angle of arctan (1/2) with positive x axis.

(angle = arctan (jcomponent/icomponent)

what level of math? also i don't need to be paid if i can you.

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q