If andres probability is 43 /60 and mai looks in the bag and sees that there are only 6 blocks in the bag . Should Adre change his estimate based on this information if so what should the new estimate be ? If not explain your reasoning

Andre picks a block out of a bag 60 times and notes that 43 of them were green.

What should Andre estimate for the probability of picking out a green block from this bag?

Mai looks in the bag and sees that there are 6 blocks in the bag. Should Andre change his estimate based on this information? If so, what should the new estimate be? If not, explain your reasoning.

The probability of picking out a green block is 43/60.

Andre shall not change his estimate based on this information because only the number of blocks left are told but the color of the blocks are still unknown. If those blocks are not green, then there is no need to change the estimate.

Explanation:

Probability is a numerical portrayal of how likely an occasion is to happen or how likely it is that a recommendation is valid. Likelihood is a number somewhere in the range of 0 and 1, where, generally, 0 demonstrates inconceivability and 1 shows sureness.

To calculate the probability, divide the number of events with the possible outcomes. This will give us the likelihood of a solitary occasion happening. On account of rolling a 3 on a bite the dust, the quantity of occasions is 1 (there's just a solitary 3 on each kick the bucket), and the quantity of results is 6.

associative property hopes this ! : )

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2