Mathematics, 28.02.2020 18:58 karenjunior
Two stones are thrown vertically upward with matching initial velocities of 48ft/s at timet= 0. One stone is thrown from the edge of a bridge that is 32 ftabove the ground and the other stone is thrown from ground level. The heightof the stone thrown from the bridge aftertseconds isf(t) =−16t2+ 48t+ 32,and the height of the stone thrown from the ground aftertseconds isg(t) =−16t2+ 48t.
Answers: 1
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Two stones are thrown vertically upward with matching initial velocities of 48ft/s at timet= 0. One...
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