Which of the following completes the proof?

Triangles ABC and EDC are formed from segments BD and AC, in which point C is between points B and D and point E is between points A and C.

Given: Segment AC is perpendicular to segment BD

Prove: ΔACB ~ ΔECD

Reflect ΔECD over segment AC. This establishes that _. Then, translate point E' to point A. This establishes that _. Therefore, ΔACB ~ ΔECD by the AA similarity postulate.

∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC
∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC
∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC
∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC
There is a picture included if you need it
I need a correct answer!!!