Please help IXL geometry!!

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc BCD = 2*(angle A)

arc BCD = 2*(59)

arc BCD = 118 degrees

arc BCD combines with minor arc AB to get

(minor arc AB)+(arc BCD) = (137)+(118) = 255

Subtract this from 360 to get

360 - 255 = 105

This is the measure of minor arc AD as this is the missing portion to form a full circle.

In other words,

(minor arc AD) + (arc BCD) + (minor arc AB) = 105 + 118 + 137 = 360

2.83941151 would be the answer you're looking for! : )