Let U = {-7, -6, -3, 2, 3, 6, 10, 12, 17, 18}, A = {-7, -3, 3, 10, 17}, B = {-6, 2, 6, 12, 18}, and C = {-7, -6, 2, 3, 12, 17}. Find each set. (Enter your answers using roster notation. Enter {} or ∅ for the empty set.)
(a) (A intersection B) union C =

(b) (A union B union C)c =

(c) (A intersection B intersection C)c

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

1. 34

2. 268

3. x=14.4

step-by-step explanation:

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40