What is the equation of the line that is parallel to 4x-3y=6 and
passes through the point (3,-5)?

-3y = -4x + 6

3y = 4x - 6

y = (4/3)x - 2

y + 5 = (4/3)(x - 3)

y + 5 = (4/3)x - 4

y = (4/3)x - 9

Step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this