Which transformations could be performed to show that △ABC is similar to △A"B"C"? a reflection over the x-axis, then a dilation by a scale factor of 3 a reflection over the x-axis, then a dilation by a scale factor of One-third a 180° rotation about the origin, then a dilation by a scale factor of 3 a 180° rotation about the origin, then a dilation by a scale factor of One-third

answer: Option D.

Step-by-step explanation:

If two triangles ΔABC and ΔA'B'C' are similar then we take point C of ΔABC to find the transformation performed form C to C'.

Coordinates of C are (0, 3) and the coordinates of C' are (0, -1).

This shows that C is rotated 180° about origin to get the new coordinates as (0, -3) and then new coordinates were dilated by 1/3 which forms C' as (0, -1)

Therefore option D is the correct option.

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled

step-by-step explanation:

tangent z: 4/3

cosine y: 4/5

cotangent y: 4/3