The height in feet of a skydiver t seconds after deploying her parachute is given by h(t) = -300t + 1000. A ball is thrown up toward the skydiver, and after t seconds, the height of the ball in feet is given by h(t) = -16t2 + 100t. When does the ball reach the skydiver?

Step-by-step explanation:

Height of sky diver

           h(t) = -300t + 1000

Height of ball

            h(t) = -16t² + 100t

We need to find when does the ball reach the skydiver

That is both heights are equal

               -300t + 1000 = -16t² + 100t

                 16t² - 400t + 1000 = 0

                 t = 22.18 s   or t = 2.81 s  

The ball reaches skydiver at 2.81 seconds.

answer

106 emergencies

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.