A random sample of n = 755 US cell phone users age 18 and older in May 2011 found that the average number of text messages sent or received per day is 41.5 messages,32 with standard error about 6.1.a. Use the information from the sample to give the best estimate of the population parameter. b. Find a 95% confidence interval for the mean number of text messages.

a)

b) 95% Confidence interval:  (29.5,53.5)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 755

Sample mean = 41.5

Standard Error = 6.1

a) estimate of the population parameter

Parameter of interest:

Mean number of text messages sent or received per day

The population mean is best estimated by the sample mean

b) 95% confidence interval for the mean number of text messages.

95% Confidence interval:

Putting the values, we get,

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step-by-step explanation:

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step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.