A bank loaned out $13 comma 00013,000, part of it at the rate of 8 %8% per year and the rest at 18 %18% per year. If the interest received in one year totaled $20002000, how much was loaned at 8 % ?

$3400 was loaned out at 8% and $9600 was loaned out at 18%

Step-by-step explanation:

Let Amount loaned out at 8%=$A

Let Amount loaned out at 18%=$B

Total Amount Loaned = $13,000

A + B = 13000 .....(i)

Simple Interest =

Interest on A=

interest on B=

Total Interest =

So, i.e. ......(ii)

Next we solve the two equations simultaneously

A + B = 13000 .....(i)

......(ii)

From (i) A=13000-B

Substituting into (ii)

8(13000-B)+18B=200000

104000-8B+18B=200000

10B=200000-104000=96000

B=9600

Recall A + B = 13000

A + 9600 = 13000

A=13000-9600=3400

Therefore: A= $3400 and B=$9600

answer: y=4000x+14000

step-by-step explanation: