What equation of the line passes through the point (6,-6) and has a slope of -5/3

Y= -13/3x + 10

Step-by-step explanation:

use the point slope equation of y-y1=m(x-x1).

y is variable

y1 is the Y value in the point so -6

m is the slope so -5/3

x is a variable

x1 is in the point given 6

y-(-6)=-5/3(x-6)

now just solve the equation using algebra techniques and you get the answer

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

its adding 5.5 each time

step-by-step explanation: