An egg is thrown off the top of a building. Its height in meters above
the ground can be approximated by the polynomial 300 + 2t - 4.9t",
where t is the time since it was thrown in seconds.
a. How high is the egg above the ground after 5 seconds?
b. How high is the egg above the ground after 6 seconds?

Here we must work with the height equation of an egg that was thrown off the top of a building.

The solutions are:

a) 187.5 meters above the ground.

b) 135.6 meters above the ground.

So the height equation, in meters, as a function of time, in seconds, is:

h(t) = -4.9*t^2 + 2*5 + 300

a) We want to know how high is the egg after 5 seconds, so we just need to evaluate the given function in t = 5.

h(5) =  -4.9*5^2 + 2*5 + 300 = 187.5

This means that after 5 seconds, the egg is 187.5 meters above the ground.

b) We do the exact same thing, this time evaluating in t = 6.

h(6) =  -4.9*6^2 + 2*6 + 300 = 135.6

So after 6 seconds, the egg is 135.6 meters above the ground.

If you want to learn more, you can read:

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a)187.5 m

b)135.6 m

Step-by-step explanation:

Hi, to solve this problem we simply have to replace the variable "t" in the equation by the values given in each option.

h (height) =300 + 2t - 4.9t²

For a) t = 5 sec

Replacing 5 for t , and solving for h:

h= 300 + 2(5) - 4.9(5)² = 300 + 10 - 122.5=187.5 m

Repeating the process:

For b) t=6 sec

h= 300 + 2(6) - 4.9(6)² = 300 + 12 - 176.4=135.6 m

Feel free to ask for more if needed or if you did not understand something.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

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step-by-step explanation: