In a survey of 200 employees, 65% agreed that the management of the cafeteria should be changed. If the confidence interval is 95%, the margin of error for this survey is +/- 6.75% and the maximum number of employees who could have agreed is about?

a. 144 b. 140 c. 136

Option A) 144

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 200

Margin of error =

Confidence interval:

Putting values:

Thus, maximum proportion is

Maximum number of employees who could have agreed =

This, approximately maximum 144 employees agreed that the management of the cafeteria should be changed.

Option A) 144

The answers are: in the first one +/- 6.75% and the second one: 144.

Step-by-step explanation:

I just did it on Edmentum.

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23