How do I solve #4 a-c?

Step-by-step explanation:

4a) By repeating the error pattern found in the previous examples, the last example would be 638

4b) Looking at the examples, the multiplication was wrongly done. In multiplying, the unit term was multiplied first. This is right. The error was that the tens term was not added to the product of the multiplier and the tens term. The remainder was neglected.

c) the student should always add the tens from the product of the unit term and the multiplier to the product of the tens term and the multiplier. For example, the first one would be

8 × 6 = 48

You put down 8 and add 4(tens term) to the product of the tens term and the multiplier(4 + 8×3 = 28)

The solution becomes 288

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent