Paul, who is self employed, placed $30,000 in an account that pays 6% annual interest, compounded quarterly. How much interest was earned in 10 years?

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 30000

r = 6% = 6/100 = 0.06

n = 4 because it was compounded 4 times in a year.

t = 10 years

Therefore,.

A = 30000(1 + 0.06/4)^4 × 10

A = 30000(1 + 0.015)^40

A = 30000(1.015)^40

A = $54421

The amount of interest earned after 10 years is

54421 - 30000 = $24421

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!