Does anyone know this

The value of x is 20.

Solution:

Sides of one triangle are 2x – 4 and 39.

Sides of another triangle are x + 6 and 24.

Property of similar triangle:

If two triangles are similar then their corresponding angles are congruent and the corresponding sides are in the same ratio.

Do cross multiplication.

Divide by 2 on each of the term.

Solve using quadratic equation.

Ignore the negative term, because if you substitute this you will get a negative terms only. But length of sides cannot be in negative measures.

Therefore x = 20.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation