Mathematics, 26.02.2020 17:35 stinematesa

The Ming family has a backyard kiddie pool with the dimensions shown. After a lot of splashing one afternoon, the pool is only half full.

2
ft
2 ft
4
ft
4 ft
What is the volume of water remaining in the pool?

Answers: 3

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Answer from: amortalstardev

The volume of water remaining in the pool = 16 ft³

Step-by-step explanation:

To Determine:

What is the volume of water remaining in the pool?

Information Fetching and Solution Steps:

As the statement suggests the Ming family has a backyard kiddie pool with the dimensions 2 × 4 × 4 .After a lot of splashing one afternoon, the pool is only half full.

As the pool contains the dimensions: 2 × 4 × 4

Volume of water in pool = length × width × depth

= 2 × 4 × 4

= 32 ft³

As it is stated that after a lot of splashing one afternoon, the pool is only half full.

So, the volume of water remaining in the pool will be: 32/2 = 16 ft³

Therefore, the volume of water remaining in the pool = 16 ft³

Answer from: Quest

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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