Find the number of pairs (a, b) of integers such that
a+2/a+5=b/3

  6

Step-by-step explanation:

The expression can be rearranged to ...

  b = 3 -9/(a+5)

In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.

The attached table shows the values (a, b) = (x₁, f(x₁)).

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3