Suppose the vector-valued function r(t) = < f(t) ,g(t) ,h (t) > is smooth on an interval containing the point < f(t0) ,g(t0) ,h(t0) > . The line tangent to r(t) at t = t0 is the line parallel to the tangent vector r'(t0) that passes through < f(t0),g(t0),h(t0)> . Find the line tangent to the curve at t = t0. r(t)=(2t-1,9t+5,t^2), t0= 1 The tangent line is < , , > .

Step-by-step explanation:

r' = <f',g',h'> = <2,9,2t>

So, with t0=1,

r(1) = <1,14,1>

r'(1) = <2,9,2>

Now, what is the line through r(1), in the direction r'(1) ?

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

idkit the do u know da way and ligma consumed ninja

step-by-step explanation: