The frequency of a vibrating guitar
string varies inversely as its length.
Suppose a guitar string 0.65 meters long
vibrates 4.3 times per second. What
frequency would a string 0.5 meters long
have?

5.59 per seconds

Step-by-step explanation:

F is inversely proportional to L i.e

F & 1/L

F = K/L

FL = K

But F = 4.3, L = 0.65

K = FL = 4.3 x 0.65

K = 2.795

Now, we can find F when L = 0.5 by doing the following:

F = K/L

F = 2.795/0.5

F = 5.59 per seconds

step-by-step explanation:

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