If m RST = 65, m QST = 2x, and m QSR = 3x - 10, what is the value of x?

First, draw a quadrilateral figure QRST. Then, label angles RST, QST, and QSR.

Given:

mRST = 65

mQST = 2x

mQSR = 3x - 10

From the figure, angle RST is the sum of angles QST and QSR. Therefore:

mRST = mQST + mQSR

Substituting the values, the equation becomes:

65 = 2x + (3x -10)

Solve for x:

x = 15

Second awnser :

Upon drawing the triangles given, it may be observed that they share one common side, ST. Hence, m QSR is the sum of m RST and m QST. Mathematically,

                        3x - 10 = 65 + 2x

The value of x from the equation generated above is 75. Thus, the answer to the question above is 75.  

Hope i got it

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: