The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is measured in meters. Find the velocity of the particle for t = 7 seconds.

152 m/s
47 m/s
733 m/s
299 m/s

299 m/s

Step-by-step explanation:

The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

v(t) = 6t^2 + 5

Now input 7 in for t to find the velocity.

v(7) = 6(7)^2 + 5

v(7) = 299 m/s

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

3

step-by-step explanation: