Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percent faster than the average speed of car X, how many hours did it take car Y to travel the route?

Step-by-step explanation:

Both cars, X and Y travelled 80 miles each.

Speed = distance/time

If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

80/2 = 40 mph

If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

40 + 0.5 × 40 = 60 mph

Time = distance/speed

Therefore, time taken by car Y to travel 80 miles is

80/60 = 1.33 hours

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour