Find the value of x and y in these equation.
(a^x*b^y)^(1/6)=a^(1/2)*b^-(1/3)

x=3 y=-2

Step-by-step explanation:

you must take the right part of the equation and express it as (something)^1/6

you know that the general formula is (a^b)^c = a^(b*c)

and (ab)^c = (a^c)*(b^c)

so you must reach a situation where you express everything ^1/6

a^(1/2) = a^(3/6) = (a^3)^1/6

b^(-1/3) = b^(-2/6)=(b^-2)^1/6

AND

((a^3)^1/6)*((b^-2)^1/6) = (a^3*b^-2)^1/6

therefore

x=3 and y=-2

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

brainliest

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol