Pls help geo/ trig

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°. Building A is 40 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 66.57 feet taller than building B
Building A; it is around 33.29 feet taller than building B
Building B; it is around 66.57 feet taller than building A
Building B; it is around 33.29 feet taller than building A

Solution:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°

Building A is 40 feet away, and building B is 60 feet away

This forms a right angled triangle

height of building is the perpendicular

Distance between kayson and building forms the base ( adjacent)

If the height of the building A is x feet, then

Thus, height of building A is 66.57 feet

Building B is 60 feet away

If the height of building is y feet,

Thus, building B is taller

Building B - building A = 99.86 - 66.57 = 33.29 feet

Thus building B is taller and it is around 33.29 feet taller than building A

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.