A ball is launched from ground level directly upward at 39.2 m/s. The height can be modeled by the function f(t)=-4.9t^2+39.2t. For how long Is the ball at or above a height of 34.3 meters

true

step-by-step explanation:

answer: b.36 feet

step-by-step explanation:

17

step-by-step explanation:

51/3=17

thus 17 is your answer.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb