A city that had 8000 thousand people at the beginning of the year 2000 has been decreasing by 3.2% per year. What is the 1-year percent change in the city's population?

7,744 (96.8% of population at the beginning of the year)

Step-by-step explanation:

Population of the city at the beginning of the year = 8000people

Yearly percentage decrease = 3.2%

This means at the end of the first year the population reduces by 3.2% which gives 3.2%of 8000

= 3.2/100 × 8000

= 3.2 × 80

= 256

This shows that the population decreases by 256 at the end of first year.

To get the 1year percentage change in population, we will subtract the percentage decrease in Population from the initial population to give;

8000 - 256

= 7,744

7,744population remains after 1year wish is (100-3.2)% i.e 96.8% of the population at the beginning of the year.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

$450 i think. hope this ☺