An archer hits a bull’s-eye with a probability of 0.09, and the results of different attempts can be taken to be independent of each other. If the archer shoots nine arrows, what is the variance of the number of bull's-eyes scored?

Variance = 0.858

Step-by-step explanation: The variance formulae for a probability distribution is given below as

Variance = √npq

Where n = number of times experiment was performed = 9

p = probability of success = 0.09

q = probability of failure = 1 - p = 1 - 0.09 =0.91

Variance = √9×0.09×0.91

Variance = √0.7371

Variance = 0.858

answer: i oofed

step-by-step explanation:

oofed=wow