From a circular card sheet of radius 28 cm, two circles of radii 7 cm each and a rectangle of length 3 cm and breadth 2 cm are removed. Find the area of the remaining sheets

2150cm^2

Step-by-step explanation:

In this question, there is a certain circular shape. Now, from this circular shape, 2 circles and 1 rectangle have been made. We are now asked to find the area of the remaining sheet.

Mathematically, the area of the remaining sheet is the area of the circular card sheet minus the area of the 2 circles and rectangle.

Now, we need to find the value of 3 areas I.e the areas of the circular sheet, the area of the circle(they are the same) and the area of the rectangle.

Mathematically, the area of a circle is

A = πr^2

For the whole circular sheet, the value of the radius is 28cm

A = 22/7 * 28 * 28 = 2464cm^2

The Area of the two circles made is

Mathematically, the area of a circle is

A = πr^2

Here, our r is 7cm

A = 22/7 * 7 * 7

A = 154cm^2

Since the circles are 2 in number, the total area here is thus 154 * 2 = 308cm^2

The area of the rectangle is L * B = 2cm * 3cm = 6cm^2

The area of the remaining part of the circular card sheet is: 2464 - 308 - 6 = 2150cm^2

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

ljn

step-by-step explanation: