Mathematics, 25.02.2020 01:36 ozzy1146

Find parametric equations for the tangent line to the given curve at the point(213252656). The curve and the tangent line must have the same velocity vector at this point.

x(t)=1+4ty(t)=3t32?2tz(t)=4t2+6t+6
x(t)=
y(t)=
z(t)=
Give the unit tangent vector to the curve at (213252656)
T=

Answers: 3

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Find parametric equations for the tangent line to the given curve at the point(213252656). The curve and the tangent line must have the same velocity vector at this point. x(t)=1+4ty(t)=3t32?2tz(t)=4t2+6t+6 x(t)= y(t)= z(t)= Give the unit tangent vector to the curve at (213252656) T=

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Another question on Mathematics

Find parametric equations for the tangent line to the given curve at the point(213252656). The curve and the tangent line must have the same velocity vector at this point.

x(t)=1+4ty(t)=3t32?2tz(t)=4t2+6t+6
x(t)=
y(t)=
z(t)=
Give the unit tangent vector to the curve at (213252656)
T=