Moore's law says that the number of transistors in a dense integrated circuit increases by 41% every year.
In 1974. a dense integrated circuit was produced with 5000 transistors.
Which expression gives the number of transistors in a dense integrated circuit in 1979?
Choose 1

5000 - 0.415

5000(1 +0.41)

5000+ 0.41

5000 + (1 +0.41)5

Solution:

The increasing function is given as:

Where,

y is the future value

a is the initial value

r is the growth rate

t is the number of years

From given,

a = 5000

t = 1974 to 1979 = 5 years

Substituting the values in formula,

Thus the expression gives the number of transistors in a dense integrated circuit in 1979 is found

step-by-step explanation:

answers available in this download

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answer: 10 meter

step-by-step explanation:

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