Please explain by calculation, thank you!

A manufacturing process has a 3% defect rate. Inspectors catch 95% of defects but also fail 5% of nondefective parts. If we pick a part at random from all those that pass inspection, what is the probability that part is actually defective? Is the event "inspection outcome correct" independent of the outcome of the manufacturing process?

a)5%
b)0.16%
c)0.5%

correct option is b)0.16%

Step-by-step explanation:

given data

defect rate P(defect ) = 3 % = 0.03

Inspectors catch = 95%  = 0.95

fail nondefective =  5% = 0.05

solution

we get here  P(No Defect)  that is

P(No Defect)  = 1 - P( Defect)   .........1

P(No Defect)  = 1 - 0.03

P(No Defect)  = 0.97

and

P(Pass | Defect)  will be

P(Pass | Defect)  = 1 - Inspectors catch   ...........2

P(Pass | Defect) = 1 - 0.95

P(Pass | Defect)  = 0.05  

and

P(Pass | No Defect) is

P(Pass | No Defect) = 1 - fail non defective    ..............3

P(Pass | No Defect) = 1 - 0.05

P(Pass | No Defect) =  0.95

so now we apply here Baye's theorem

so

P(Defective | Pass)  is

P(Defective | Pass)  =  

P(Defective | Pass)  = 0.0016

P(Defective | Pass)  = 0.16 %

so correct option is b)0.16%

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4