20 subtracted from three times a number is 6 more than the number

Solution:

Given statement is:

20 subtracted from three times a number is 6 more than the number

We can translate the sentence into algebraic expression

Let "a" be the unknown number

Then,

20 subtracted from three times "a" is 6 more than "a"

Which means,

3a - 20 = 6 + a

3a - a = 6 + 20

2a = 26

Divide both sides by 2

a = 13

Thus the number is 13

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

7

step-by-step explanation:

the answer would be 7