Consider the point (8 2) and the line L given by the equation y = 4x - 6 what is the equation of the line in slope intercept form passing through point P and perpendicular to line L

y = -x/4 + 4 (slope intercept form)

Step-by-step explanation:

From Equation of the line L, y=4x - 6 and comparing with the general equation of line, y=mx+c, we have,

m1 = 4

For perpendicularity:

m1m2 = -1

m2 = -1/4

Hence, the equation of the line passing through (8,2) and perpendicular to L is

y - y1 = m2(x-x1)

y - 2 = -1/4(x-8)

y-2 = -x/4 + 2

y = -x/4+2+2

y = -x/4 + 4 (slope intercept form)

where slope, m2= -1/4, c = 4

6.5

step-by-step explanation:

you said it was in the question

~courtney

6 cm

step-by-step explanation: