Find the probability that when a couple has three children, at least one of them is a boy. (Assume that boys and girls are equally likely.)

The probability that at least 1 of the 3 children is a boy is 0.875.

Step-by-step explanation:

The probability of a baby born being a girl or a boy is same, i.e.

P (G) = P (B) = 0.50.

A couple has 3 children.

Let X = number of boys.

The random variable X follows a Binomial distribution. The probability of a Binomial distribution is computed using the formula:

Compute the probability that at least 1 of the 3 children is a boy as follows:

P (At least 1 boy) = 1 - P (No boys)

              P (X ≥ 1) = 1 - P (X = 0)

Thus, the probability that at least 1 of the 3 children is a boy is 0.875.

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

i can answer this question sweetie!

step-by-step explanation: