Suppose I make several time measurements, and compute an average time of 3.4 s, with a standard deviation of 0.8 s and an SDOM of 0.2 s. If I make another time measurement, how often would I expect the result to be smaller than 2.6s\

The result will be smaller than 2.6s, 16% of the time.

Step-by-step explanation:

This is a normal distribution problem

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ

x = the random value = 2.6 s

xbar = mean = the average = 3.4 s

σ = standard deviation = 0.8 s

z = (2.6 - 3.4)/0.8 = - 1

P(x < 2.6) = P(z < - 1) = 1 - P(z ≥ - 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159 = 16%

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

35 is an outlier

step-by-step explanation: