Computer battery A has 4/5 of its power remaining. Computer battery B has 9/20 of its power remaining. How much more power does computer battery A have compared to computer battery B?

7/20

Step-by-step explanation:

GIven:

Battery A = 4/5 remaining

Battery B = 9/20 remaining

assuming both batteries are otherwise identical (except for charge level remaining), then,

Battery A - Battery B

= 4/5 - 9/20

we need to convert both fractions to same denominator to perform the subtraction easily. Note that the Least Common Multiple for 5 and 20 is 20, hence we convert both denominators to 20,

Battery A - Battery B

= 4/5 - 9/20

= (4/5) (4/4) - 9/20

= 16/20-9/20

= 7/20

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

take it another