Please correct my mistake with this limit

Step-by-step explanation:

The first four lines are correct.  Your mistake is after you get to this part:

lim(n→0) (2 sin²(n/2) / n)

In the fifth line, it looks like you try to write this limit as:

2 lim(n→0) ¼ (sin (n/2) / (n/2))²

But these are not the same.  You're introducing another n in the denominator.

Here's what you should do instead:

lim(n→0) (2 sin²(n/2) / n)

lim(n→0) (sin²(n/2) / (n/2))

lim(n→0) (sin (n/2) / (n/2)) × lim(n→0) (sin (n/2))

1 × 0

0

Now when you plug this in, you get (0 + 1) / (0 − 1) = -1.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: