A simple random sample of size nequals64 is obtained from a population with mu equals 75 and sigma equals 8.
(a) Describe the sampling distribution of x overbar.
(b) What is Upper P (x overbar greater than 76.55 )?
(c) What is Upper P (x overbar less than or equals 72.9 )?
(d) What is Upper P (73.5 less than x overbar less than 77.05 )?

a) Approximately normal with mean 75 and standard deviation s = 1.

b) 0.0606

c) 0.0179

d) 0.9110

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , a large sample size, of at least 30, can be approximated to a normal distribution with mean and standard deviation

In this problem, we have that:

(a) Describe the sampling distribution of x overbar.

Approximately normal with mean 75 and standard deviation s = 1.

(b) What is Upper P (x overbar greater than 76.55 )?

This is 1 subtracted by the pvalue of Z when X = 76.55.

By the Central Limit Theorem

has a pvalue of 0.9394.

1 - 0.9394 = 0.0606

(c) What is Upper P (x overbar less than or equals 72.9 )?

This is the pvalue of Z when X = 72.9. So

has a pvalue of 0.0179.

(d) What is Upper P (73.5 less than x overbar less than 77.05 )?

Pvalue of Z when X = 77.05 subtracted by the pvalue of Z when X = 73.5 So

X = 77.05

has a pvalue of 0.9778

X = 73.5

has a pvalue of 0.0668

0.9778 - 0.0668 = 0.9110

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

step-by-step explanation:

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