A truck can be rented from company A for $80 a day plus $0.20 per mile. Company B charges $60 per mile plus $0.30 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.

The number of miles in a day at which the rental costs for Company A and Company B are the same is 200 miles.

Explanation:

Let the number of miles be m

Rent from Company A = $80 + m X $0.2

Rent from Company B = $60 + m X $0.3

Rental costs of both company A and B are same

So,

$80 + m X $0.2 = $60 + m X $0.3

$80 + $0.2m = $60 + $0.3m

$80 - $60 = $0.1m

$20 = $0.1m

m = 200

Therefore, number of miles in a day at which the rental costs for Company A and Company B are the same is 200 miles.

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step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!